# How Many Cement Bags Required in 100 Sq Ft RCC Slab?

Total 7.6 bags cement each of 50 kg is required for 100 square feet rcc slab when the thickness of slab is 4 inch, and 10.5 bags cement is required when thickness of slab is 5 inch. Read the complete post to understand in detail.

## Cement Bags Required in 100 Sq Ft RCC Slab of 4 Inch

To calculate the number of cement bags required in 100 square feet slab of 4 inch thickness, we have some requirements and considerations in the slab.

**Requirements and Considerations for Slab**

- Size of slab = 100 square feet
- Thickness of slab = 4 inch
- Shrinkage factor = 1.54 (54% extra of wet volume)

**Volume of Slab (Concrete Work)**

Volume of slab

= Area of slab × Thickness of slab

= 100 square feet × (4 inch/12) feet

=

**33.33 Cubic Feet**Hence, total volume of rcc work = 33.33 cubic feet (wet concrete).

**Dry Volume of Concrete**

Total volume of dry concrete

= 1.54 × 33.33 Cubic Feet

=

**51.33****Cubic Feet****1. Volume of Cement in 100 Square Feet Slab (M20 Grade Concrete)**

Ratio of concrete (M20) = 1:1.5:3 (Cement : Sand : Coarse Aggregate)

Sum of ratio = 1+1.5+3 = 5.5

Volume of cement in 100 square feet slab

= (Ratio of cement/ Total ratio of concrete) × Total volume of dry concrete

= (1/5.5) × 51.33 Cubic Feet

=

**9.33****Cubic Feet**or**0.2642 m³**Since, density of cement is 1440 m³/kg

Hence, the weight of cement is 0.2642 m³ × 1440 kg/m³

=

**380.4 kg**or**7.6 Bags**of cement each 50 kg**2. Volume of Cement in 100 Square Feet Slab (M25 Grade Concrete)**

Ratio of concrete (M25) = 1:1:2 (Cement : Sand : Coarse Aggregate)

Sum of ratio = 1+1+2 = 4

So, Volume of cement in 100 square feet slab

= (Ratio of cement/ Total ratio of concrete) × Total volume of dry concrete

= (1/4) × 51.33 Cubic Feet

=

**12.833****Cubic Feet**or**0.3634 m³**Since, density of cement is 1440 m³/kg

Hence, the weight of cement is 0.3634 m³ × 1440 kg/m³

=

**523.3 kg**or**10.5 Bags**of cement each 50 kg## Cement Bags Required in 100 Sq Ft RCC Slab of 5 Inch

To calculate the number of cement bags required in 100 square feet slab of 5 inch thickness, we have some requirements and considerations in the slab.

**Requirements and Considerations for Slab**

- Size of slab = 100 square feet
- Thickness of slab = 5 inch
- Shrinkage factor = 1.54 (54% extra of wet volume)

**Volume of Slab (Concrete Work)**

Volume of slab

= Area of slab × Thickness of slab

= 100 square feet × (5 inch/12) feet

=

**41.67 Cubic Feet**Hence, total volume of rcc work = 41.67 cubic feet (wet concrete).

**Dry Volume of Concrete**

Total volume of dry concrete

= 1.54 × 41.67 Cubic Feet

=

**64.17****Cubic Feet****1. Volume of Cement in 100 Square Feet Slab (M20 Grade Concrete)**

Ratio of concrete (M20) = 1:1.5:3 (Cement : Sand : Coarse Aggregate)

Sum of ratio = 1+1.5+3 = 5.5

Volume of cement in 100 square feet slab

= (Ratio of cement/ Total ratio of concrete) × Total volume of dry concrete

= (1/5.5) × 64.17 Cubic Feet

=

**11.67****Cubic Feet**or**0.33 m³**Since, density of cement is 1440 m³/kg

Hence, the weight of cement is 0.33 m³ × 1440 kg/m³

=

**475.2 kg**or**9.5 Bags**of cement each 50 kg**2. Volume of Cement in 100 Square Feet Slab (M25 Grade Concrete)**

Ratio of concrete (M25) = 1:1:2 (Cement : Sand : Coarse Aggregate)

Sum of ratio = 1+1+2 = 4

So, Volume of cement in 100 square feet slab

= (Ratio of cement/ Total ratio of concrete) × Total volume of dry concrete

= (1/4) × 64.17 Cubic Feet

=

**16.0425****Cubic Feet**or**0.453 m³**Since, density of cement is 1440 m³/kg

Hence, the weight of cement is 0.453 m³ × 1440 kg/m³

=

**652.32 kg**or**13 Bags**of cement each 50 kg**Note:**This quantity just for reference and it is based on above assumptions and it may vary depending upon material type and other design changes.